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u^2-24u+108=0
a = 1; b = -24; c = +108;
Δ = b2-4ac
Δ = -242-4·1·108
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12}{2*1}=\frac{12}{2} =6 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12}{2*1}=\frac{36}{2} =18 $
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